3.6: Solving Arithmetic Expressions in MIPS Assembly

Last updated
Save as PDF

Page ID: 27111

\( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\)

Using the MIPS arithmetic operations covered so far, a program can be created to solve equations. For example the following pseudo code program, where the user is prompted for a value of x and the program prints out the results of the equation 5x2 + 2x + 3.

main
{
    int x = prompt("Enter a value for x: ");
    int y = 5 * x * x + 2 * x + 3;
    print("The result is: " + y);
}

This program is implemented in MIPS below.

Program 3-3: Program to calculate 5*x^2 + 2*x + 3

# File:      Program3-3.asm
# Author:    Charles Kann
# Purpose:   To calculate the result of 5*x^ + 2*x + 3

.text
.globl main
main:
    # Get input value, x
    addi $v0, $zero, 4
    la $a0, prompt
    syscall
    addi $v0, $zero, 5
    syscall
    move $s0, $v0
    
    # Calculate the result of 5*x*x + 2* x + 3 and store it in $s1.
    mul $t0, $s0, $s0
    mul $t0, $t0, 5
    mul $t1, $s0, 2
    add $t0, $t0, $t1
    addi $s1, $t0, 3
    
    # Print output
    addi $v0, $zero, 4    # Print result string
    la $a0, result
    syscall
    addi $v0, $zero, 1    # Print result
    move $a0, $s1
    syscall
    
    #Exit program
    addi $v0, $zero, 10
    syscall
.data
prompt: .asciiz "Enter a value for x: "
result: .asciiz "The result is: "