Skip to main content
Engineering LibreTexts

6.3: Exercises

  • Page ID
    24264
  • \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\)

    Exercise 6.1

    Suppose the output \(y(t)\) of a system is related to the input \(u(t)\) via the following relation:

    \[y(t)=\int_{0}^{\infty} e^{-(t-s)} u(s) d s\nonumber\]

    Verify that the model is linear, time-varying, non-causal, and not memoryless.

    Exercise 6.2

    Suppose the input-output relation of a system is given by

    \[y(t)=\left\{\begin{array}{ll}
    u(t) & \text { if }|u(t)| \leq 1 \\
    \frac{u(t)}{\mid u(t)} \mid & \text { if }|u(t)|>1
    \end{array}\right.\nonumber\]

    This input-output relation represents a saturation element. Is this map nonlinear? Is it memoryless?

    Exercise 6.3

    Consider a system modeled as a map from \(u(t)\) to \(y(t)\), and assume you know that when

    \[u(t)=\left\{\begin{array}{ll}
    1 & \text { for } 1 \leq t \leq 2 \\
    0 & \text { otherwise }
    \end{array}\right.\nonumber\]

    the corresponding output is

    \[y(t)=\left\{\begin{array}{ll}
    e^{t-1}-e^{t-2} & \text { for } t \leq 1 \\
    2-e^{1-t}-e^{t-2} & \text { for } 1 \leq t \leq 2 \\
    e^{2-t}-e^{1-t} & \text { for } t \geq 2
    \end{array}\right.\nonumber\]

    In addition, the system takes the zero input to the zero output. Is the system causal? Is it memoryless?

    A particular mapping that is consistent with the above experiment is described by

    \[y(t)=\int_{-\infty}^{\infty} e^{-|t-s|} u(s) d s\ \tag{6.24}\]

    Is the model linear? Is it time-invariant?

    Exercise 6.4

    For each of the following maps, determine whether the model is (a) linear, (b) timeinvariant, (c) causal, (d) memoryless.

    1. \[y(t)=\int_{0}^{t}(t-s)^{3} u(s) d s\nonumber\]
    2. \[y(t)=1+ \int_{0}^{t}(t-s)^{3} u(s) d s\nonumber\]
    3. \[y(t)=u^{3}\tag{t}\]
    4. \[y(t)=\int_{0}^{t} e^{-t s} u(s) d s\nonumber\]

    This page titled 6.3: Exercises is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by Mohammed Dahleh, Munther A. Dahleh, and George Verghese (MIT OpenCourseWare) via source content that was edited to the style and standards of the LibreTexts platform; a detailed edit history is available upon request.