Skip to main content
Engineering LibreTexts

5.5: Method of Sections

  • Page ID
    52781
  • \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\)

    The method of sections is a process used to solve for the unknown forces acting on members of a truss. The method involves breaking the truss down into individual sections and analyzing each section as a separate rigid body. The method of sections is usually the fastest and easiest way to determine the unknown forces acting in a specific member of the truss.

    Using the Method of Sections:

    The process used in the method of sections is outlined below.

    1. In the beginning, it is usually useful to label the members in your truss. This will help you keep everything organized and consistent in later analysis. In this book, the members will be labeled with letters.
      A truss bridge with a 30-meter span consisting of members A, D and H (left to right), each 10 meters long. The span connects to the ground with a pin joint at A's left end and a roller joint at H's right end. The endpoints of member D are attached to the top ends of two vertical members: C (left) and G (right), with the lower ends of C and G connected by a horizontal member F. Diagonal members B and I, at 20° below the horizontal, connect the left end of F to the pin joint, and the right end of F to the roller joint, respectively. Downwards forces of 60 kN and 80 kN are applied at the top ends of C and G, respectively.

      Figure \(\PageIndex{1}\): The first step in the method of sections is to label each member.

    2. Treating the entire truss structure as a rigid body, draw a free body diagram, write out the equilibrium equations, and solve for the external reacting forces acting on the truss structure. This analysis should not differ from the analysis of a single rigid body.
      Free body diagram of the truss bridge from Fig. 1 above: in addition to the downwards applied forces, the upwards reaction forces of 66.7 kN at the left end of member A and 73.3 kN at the right end of member H are shown.

      Figure \(\PageIndex{2}\): Treat the entire truss as a rigid body and solve for the reaction forces supporting the truss structure.

    3. Next, you will imagine cutting your truss into two separate sections. The cut should travel through the member that you are trying to solve for the forces in, and should cut through as few members as possible. The cut does not need to be a straight line.
      The free body diagram from Fig. 2 above is depicted with a vertical dotted line dividing the bridge down the middle.Figure \(\PageIndex{3}\): Next you will imagine cutting the truss into two parts. If you want to find the forces in a specific member, be sure to cut through that member. It also makes things easier if you cut through as few members as possible.

    4. Next, you will draw a free body diagram for either one or both sections that you created. Be sure to include all the forces acting on each section.
      • Any external reaction or load forces that may be acting at the section.
      • An internal force in each member that was cut when splitting the truss into sections. Remember that for a two-force member, the force will be acting along the line between the two connection points on the member. We will also need to guess if it will be a tensile or a compressive force. An incorrect guess now, though, will simply lead to a negative solution later on. A common strategy then is to assume all forces are tensile; then later in the solution any positive forces will be tensile forces and any negative forces will be compressive forces.
      • Label each force in the diagram. Include any known magnitudes and directions and provide variable names for each unknown.
        Free body diagram of the left side of the bridge as divided by the dotted line in Fig. 3 above. In addition to the applied and reaction forces present on A, tension forces exerted by the halves of members D, E and F that were removed from the diagram by the cut on the halves present in the diagram are included.

        Figure \(\PageIndex{4}\): Next, draw a free body diagram of one or both halves of the truss. Add the known forces, as well as unknown tensile forces for each member that you cut.

    5. Write out the equilibrium equations for each section you drew a free body diagram of. These will be extended bodies, so you will need to write out the force and the moment equations.
      • For 2D problems you will have three possible equations for each section: two force equations and one moment equation. \[ \sum \vec{F} = 0 \quad\quad\quad\quad \sum \vec{M} = 0 \] \[ \sum F_x = 0 \, ; \,\,\, \sum F_y = 0 \, ; \,\,\, \sum M_z = 0 \]
      • For 3D problems you will have six possible equations for each section: three force equations and three moment equations. \[ \sum \vec{F} = 0 \] \[ \sum F_x = 0 \, ; \,\,\, \sum F_y = 0 \, ; \,\,\, \sum F_z = 0 \] \[ \sum \vec{M} = 0 \] \[ \sum M_x = 0 \, ; \,\,\, \sum M_y = 0 \, ; \,\,\, \sum M_z = 0 \]
    6. Finally, solve the equilibrium equations for the unknowns. You can do this algebraically, solving for one variable at a time, or you can use matrix equations to solve for everything at once. If you assumed that all forces were tensile earlier, remember that negative answers indicate compressive forces in the members.
    Video lecture covering this section, delivered by Dr. Jacob Moore. YouTube source: https://youtu.be/XcRn776w22Q.

    Example \(\PageIndex{1}\)

    Find the forces acting on members BD and CE. Be sure to indicate if the forces are tensile or compressive.

    A truss bridge with a 30-meter span; the leftmost end, point A, connects to the ground with a pin joint and the rightmost end, F, connects to the ground with roller joint. The span is formed from 3 10-meter horizontal members: AB, BD, and DF. Two vertical members, BC and DE, attach to the endpoints of that span's central member and extend below it. Another horizontal member connects points C and E. The diagonal members AC and FE, each 20° below the horizontal, connect the ends of that lower horizontal member to the endpoints of the bridge span. A downwards force of 60 kN is applied at point B, and a downwards force of 80 kN is applied at point D.
    Figure \(\PageIndex{5}\): problem diagram for Example \(\PageIndex{1}\). A two-dimensional representation of a truss bridge, with a standard-orientation \(xy\)-coordinate system.
    Solution
    Video \(\PageIndex{2}\): Worked solution to example problem \(\PageIndex{1}\), provided by Dr. Jacob Moore. YouTube source: https://youtu.be/9xxmHpLB1uU.

    Example \(\PageIndex{2}\)

    Find the forces acting on members AC, BC, and BD of the truss. Be sure to indicate if the forces are tensile or compressive.

    A tower composed of trusses arranged in a long rectangle composed of 4 identical smaller rectangles that are each 10 m in length and 6 m in height. The lowest points of the tower, A on the left and B on the right, are attached to the ground with a pin joint and a roller joint respectively. Points C and D are attached to A and B respectively by vertical members, and B and C are linked by a diagonal member. At each side of the lower horizontal member of the topmost rectangular subunit, a 10-meter member protrudes horizontally and a diagonal member links the free end of the protrusion to the corresponding upper corner of the topmost rectangle. The endpoints of the protruding members experience a force downwards and to the right, at 15° from the vertical. The magnitude of the left member's force is 40 kN and the magnitude of the right member's is 50 kN.
    Figure \(\PageIndex{6}\): Problem diagram for Example \(\PageIndex{2}\). A two-dimensional representation of a tower composed of trusses, arranged in a tall rectangle made of rectangular subunits with a trapezoidal top.
    Solution
    Video \(\PageIndex{3}\): Worked solution to example problem \(\PageIndex{2}\), provided by Dr. Jacob Moore. YouTube source: https://youtu.be/Kp9U4d2qbvE.

    This page titled 5.5: Method of Sections is shared under a CC BY-SA 4.0 license and was authored, remixed, and/or curated by Jacob Moore & Contributors (Mechanics Map) via source content that was edited to the style and standards of the LibreTexts platform; a detailed edit history is available upon request.

    • Was this article helpful?