Skip to main content
Engineering LibreTexts

5.6: Example extract of Java code for binary tree delete operation

  • Page ID
    47905
  • \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\)

    private Treap1<K, V>.TreapNode deleteNode(K k, Treap1<K, V>.TreapNode node, Deleted del) {
     
    		if (node == null) {
    			return null;
    		} else if (k.compareTo(node.k) < 0) {
    			 node.left = (k, node.left, del) ;
    		} else if (k.compareTo(node.k) > 0) {
    			node.right = deleteNode(k, node.right, del);
     
    			// k.compareTo(node.k) == 0
    		} else if ( node.left == null ) {
    				del.success = true;
    				return node.right;
    		} else if ( node.right == null) {
    			  del.success = true;
    				return node.left;
    		} else if (node.left !=null && node.right != null){
    		/*
            // non-standard method,
    		// left rotate and all delete on left subtree
    
    			TreapNode tmp = node.right;
    			node.right = node.right.left;
    		    tmp.left = node;
    		    node = tmp;			
    			node.left = deleteNode(k , node.left, del);
    			
             */
    
    	    // more standard method ? doesn't disturb tree structure as much
    	    // find leftmost descendant of the right child node and replace contents
    
    			TreapNode n2 = node.right;
    			TreapNode previous2 = null;
    			while (n2.left != null) {
    				previous2 = n2;
    				n2 = n2.left;
    			}
     
    			if (previous2 != null) {
    				previous2.left = n2.right;
                    //n2 has no parent link, orphaned
    			} else {
    				node.right = n2.right;
                    //n2 has no parent link, orphaned
    			}
     
    			node.k = n2.k;
    			node.val = n2.val;
    			del.success = true;
                // once n2 out of scope, the orphaned node at n2 will be garbage collected, 
    		}
     
    		return node;
    	}
    

    5.6: Example extract of Java code for binary tree delete operation is shared under a CC BY-SA license and was authored, remixed, and/or curated by LibreTexts.

    • Was this article helpful?