Skip to main content
Engineering LibreTexts

4.9: Chapter 4 Homework Problems

  • Page ID
    102543
  • \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)

    \( \newcommand{\dsum}{\displaystyle\sum\limits} \)

    \( \newcommand{\dint}{\displaystyle\int\limits} \)

    \( \newcommand{\dlim}{\displaystyle\lim\limits} \)

    \( \newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\)

    ( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\)

    \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)

    \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\)

    \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)

    \( \newcommand{\Span}{\mathrm{span}}\)

    \( \newcommand{\id}{\mathrm{id}}\)

    \( \newcommand{\Span}{\mathrm{span}}\)

    \( \newcommand{\kernel}{\mathrm{null}\,}\)

    \( \newcommand{\range}{\mathrm{range}\,}\)

    \( \newcommand{\RealPart}{\mathrm{Re}}\)

    \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)

    \( \newcommand{\Argument}{\mathrm{Arg}}\)

    \( \newcommand{\norm}[1]{\| #1 \|}\)

    \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)

    \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\AA}{\unicode[.8,0]{x212B}}\)

    \( \newcommand{\vectorA}[1]{\vec{#1}}      % arrow\)

    \( \newcommand{\vectorAt}[1]{\vec{\text{#1}}}      % arrow\)

    \( \newcommand{\vectorB}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \( \newcommand{\vectorC}[1]{\textbf{#1}} \)

    \( \newcommand{\vectorD}[1]{\overrightarrow{#1}} \)

    \( \newcommand{\vectorDt}[1]{\overrightarrow{\text{#1}}} \)

    \( \newcommand{\vectE}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{\mathbf {#1}}}} \)

    \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)

    \(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)
    Exercise \(\PageIndex{1}\)

    Determine if the two systems below are statically equivalent.

    A horizontal rod held off the ground by two supports: one at the right end, and the other 10 feet to the left of the first. A downwards point force of 60 lbs is applied at the midpoint between these supports, and another downwards point force of 40 lbs is applied 3 feet to the left of the support on the left.
    Figure \(\PageIndex{1}\): part 1 of the problem diagram for Exercise \(\PageIndex{1}\). A horizontal bar held off the ground by two supports experiences two point forces at different points along its length.
    A horizontal rod held off the ground by two supports: one at the right end, and the other 10 feet to the left of the first. A downwards point force of 100 lbs is applied to the rod, 2 feet to the right of the support on the left.
    Figure \(\PageIndex{2}\): part 2 of the problem diagram for Exercise \(\PageIndex{1}\). A horizontal bar held off the ground by two supports experiences a single point force partway along its length.
    Solution

    No, they are not equivalent.

    Exercise \(\PageIndex{2}\)

    Determine if the set of forces in A is statically equivalent to the set of forces and moments in B.

    System A (on the left) consists of a uniform cross composed of two 60-cm rods joined at their midpoints, with an upwards force of 200 N applied to the end of the cross's left arm, a leftwards force of 200 N applied to the end of the upper arm, an upwards force of 200 N applied to the midpoint of the right arm, and a rightwards force of 100 N applied to the end of the lower arm. System B (on the right) consists of an identical cross with an upwards force of 200 N applied to the end of the left arm, a leftwards force of 100 N applied to the end of the upper arm, an upwards force of 200 N applied to the end of the right arm, a rightwards force of 200 N applied to the lower arm, and a clockwise moment of 30 N-m about the cross center.
    Figure \(\PageIndex{3}\): problem diagram for Exercise \(\PageIndex{2}\). Two uniform crosses of equal dimensions experience a set of forces (system A, left) and a set of forces and moments (system B, right).
    Solution

    No, they are not equivalent.

    Exercise \(\PageIndex{3}\)

    Determine the equivalent point load (magnitude and location) for the distributed force shown below.

    A horizontal bar 5 meters long is attached to a wall at its left end. Starting at the point 2 meters to the right of the wall, it experiences a downwards distributed force over the rest of its length that varies linearly in magnitude: starting at 50 N/m and decreasing to 20 N/m at the right end.
    Figure \(\PageIndex{3}\): problem diagram for Exercise \(\PageIndex{3}\). A horizontal bar attached to a wall at one end experiences a distributed force, which varies linearly, over part of its length.
    Solution

    \(F_{eq} = 105 \, N\)

    \(x_{eq} = 3.29 \, m\) (measured from wall)

    Exercise \(\PageIndex{4}\)

    Determine the equivalent point load (magnitude and location) for the distributed force shown below.

    A horizontal bar 18 feet long is attached to a wall at its left end. It experiences a distributed force whose magnitude starts at 0 lb/ft at the left end, increases linearly tp 600 lbs/ft at the point 6 feet to the right of the wall, and decreases linearly to 0 lb/ft at the right end of the bar.
    Figure \(\PageIndex{4}\): problem diagram for Exercise \(\PageIndex{4}\). A horizontal bar attached to a wall experiences a distributed force over its length, with magnitude varying linearly according to a piecewise force function.
    Solution

    \(F_{eq} = 5400 \, lbs\)

    \(x_{eq} = 8 \, ft\) (measured from wall)


    This page titled 4.9: Chapter 4 Homework Problems is shared under a CC BY-SA 4.0 license and was authored, remixed, and/or curated by Jacob Moore & Contributors (Mechanics Map) via source content that was edited to the style and standards of the LibreTexts platform.