21.4: Procedure

21.4.1: DC Circuit Voltages

1. Consider the circuit of Figure 21.3.1 using Vcc = 15 volts, Vee = −12 volts, Rs = 10 k\(\Omega\), Rb = 33 k\(\Omega\), Re = 22 k\(\Omega\), Rc = 15 k\(\Omega\), Rload = 20 k\(\Omega\), C1 = C2 = 10 \(\mu\)F and C3 = 470 \(\mu\)F. Using the approximation of a negligible base voltage, determine the DC voltages at the base, emitter, and collector along with the collector current, and record these in Table 21.5.1.

2. Build the circuit of Figure 21.3.1 using Vcc = 15 volts, Vee = −12 volts, Rs = 10 k\(\Omega\), Rb = 33 k\(\Omega\), Re = 22 k\(\Omega\), Rc = 15 k\(\Omega\), Rload = 20 k\(\Omega\), C1 = C2 = 10 \(\mu\)F and C3 = 470 \(\mu\)F. Make sure that the AC source is turned off or disconnected. Measure the DC voltages at the base, emitter, and collector along with the collector current, and record these in Table 21.5.1. Note, you may wish to use a transistor curve tracer or beta checker to get approximate values of beta for each of the three transistors to be used.

21.4.2: AC Circuit Voltages

3. Based on the calculated collector current, determine the resulting theoretical \(r’_e\), \(A_v\), \(Z_{in}\) and \(Z_{out}\), and record these in Table 21.5.2. Assume a beta of approximately 150 for the \(Z_{in}\) calculation.

4. Continuing with the values in Table 21.5.2 and using an AC source voltage of a 40 mV peak-peak 1 kHz sine wave, compute the theoretical AC base, emitter and load voltages, and record them in Table 21.5.3 (Theory). Note that \(R_s\) will create a voltage divider effect with \(Z_{in}\), thus reducing the signal that reaches the base. This reduced signal is then multiplied by the voltage gain and appears at the collector.

5. Set the source to a 40 mV peak-peak 1 kHz sine wave and apply to the circuit. Using the oscilloscope, place one probe at the base and the second at the emitter. Record the resulting peak-peak voltages in the first row of Table 21.5.3 (Experimental). The oscilloscope inputs should be set for AC coupling with the bandwidth limit engaged. Capture an image of the oscilloscope display.

6. Move the second probe to the load and record its peak-peak value in the first row of Table 21.5.3. Also include whether the signal is in phase or out of phase with the base signal. Capture an image of the oscilloscope display.

7. Unhook the load resistor from the output capacitor and measure the resulting collector voltage (do not connect the output capacitor to ground-simply leave it dangling). Record this value in the final column of Table 21.5.3.

8. Reattach the load resistor. Swap the transistor with the second transistor and repeat steps 5 through 7 using the second row of Table 21.5.3.

9. Reattach the load resistor. Swap the transistor with the third transistor and repeat steps 5 through 7 using the third row of Table 21.5.3.

10. Using the measured base and collector voltages from Table 21.5.3, determine the experimental gain for each transistor. From these gains determine the experimental \(r’_e\). Using the source voltage, the measured base voltages and the source resistance, determine the effective input impedances via Ohm’s law or the voltage divider rule. Finally, in similar manner and using the loaded and unloaded collector voltages along with the load resistor value, determine the experimental output impedances. Record these values in Table 21.5.4. Also determine and record the percent deviations.

21.4.3: Troubleshooting

11. Return the load resistor to the circuit. Consider each of the individual faults listed in Table 21.5.5 and estimate the resulting AC load voltage. Introduce each of the individual faults in turn and measure and record the load voltage in Table 21.5.5.

21.4.4: Computer Simulation

12. One issue with amplifiers is noise and ripple on the power supply. This will be directly coupled to output of the circuit via the collector resistor. Worse, this noise or ripple may be coupled into the base and then amplified along with the desired input signal. This can be an issue with amplifiers that use a voltage divider bias. One way to reduce this effect is to decouple the voltage divider from the base. This modification is shown in the circuit of Figure 21.3.2. Cb effectively shorts R2, sending power supply noise and ripple to ground instead of into the base. By itself this would also short the desired input signal so an extra resistor, R3 is added between the capacitor and the base. The input impedance of the circuit is approximately equal to R3 in parallel with \(\beta\) \(r’_e\). To show the effectiveness of this technique, build the circuit of Figure 21.3.2 in a simulator. Use values of Vin = 20 mV peak at 1 kHz, Vripple = 20 mV peak at 120 Hz, Vcc = 12 volts, Rs = 1 k\(\Omega\), R1 = 10 k\(\Omega\), R2 = 3.3 k\(\Omega\), R3 = 22 k\(\Omega\), Re = 4.7 k\(\Omega\), Rc = 3.3 k\(\Omega\), Rload = 1 k\(\Omega\), Cin = Cout = 10 \(\mu\)F, Cb= 100 \(\mu\)F and Ce = 470 10 \(\mu\)F. Run a Transient simulation and look at the load voltage. A very small low frequency variation should be noted. This is the 120 Hz ripple coupled in through the collector resistor. Alter the circuit by removing Cb and R3 to produce the basic voltage divider circuit (or more simply, set Cb and R3 to extremely small values such as pF and m\(\Omega\)). Rerun the simulation. The load voltage should now show a much more obvious ripple contribution, thus showing how effective the power supply decoupling components can be.