7.25: Untitled Page 170
- Page ID
- 18303
Chapter 7
At this point we make use of Eq. 7‐34 to obtain the standard constraints on mole fractions when only ethylene ( C H ) , carbon dioxide ( CO ) and 2
4
2
nitrogen ( N ) are present. This provides
2
( x
)
( x
) ( x
)
1
(37a)
C2H4 4
CO2 4
N2 4
( x
) ( x
) ( x
)
1
(37b)
C2H4 6
CO2 6
N2 6
and subtracting Eq. 37a from Eq. 37b leads to
( x
)
( x
)
(38)
C2H4 6
C2H4 4
We now make use of Eq. 7‐45 to represent the constraints on the three mole fractions as
( M
)
M
M
( M
)
(39a)
CO
6
6 4
2
CO2 4
( M
)
M
M
( M
)
(39b)
N
6
6 4
2
N2 4
( M
)
M
M
( M
)
(39c)
C H
6
6 4
2
4
C2H4 4
In Eq. 1 note that is the fraction of Stream #4 that needs to be purged, i.e.,
M M
(40)
6
4
thus the molar flow rates in Stream #6 are given by
( M
)
( M
)
(41a)
CO2 6
CO2 4
( M
)
( M )
(41b)
N2 6
N2 4
( M
)
( M
)
(41c)
C2H4 6
C2H4 4
Use of these results with Eqs. 35 leads to
C H :
( M
)
(1 )( M
)
(42a)
2
4
C2H4 5
C2H4 4
CO :
( M
)
(1 )( M
)
(42b)
2
CO2 5
CO2 4
N :
( M
)
(1 )( M )
(42c)
2
N2 5
N2 4
Material Balances for Complex Systems
317
and we can use Eq. 34b to represent the molar flow rate of ethylene in Stream #5 as
( 1 )( 1 )
( M
C
)
(43)
C2H4 5
CY
At this point we need to return to Control Volume I in order to acquire additional information needed to determine the parameter, . Beginning with Eq. 30a, we use Eq. 34a and Eq. 43 to obtain
C H :
( M
)
1 1 C 1
(44a)
C H
1
2
4
2
4
CY
Moving on to Eq. 30b, we use Eq. 32d along with Eq. 34a and Eq. 42b to obtain
2 1 1
CO :
( M
Y
)
(44b)
2
CO2 2
Y
Next we use Eq. 30c along with Eq. 34d to obtain
O :
5
( M
)
( M )
(3 Y) Y
(44c)
2
O2 1
O2 2
2
and finally we make use of Eq. 30c along with Eq. 31 to express the molar flow rate of nitrogen entering the system as
N :
5
( M
)
(3 Y) Y
(44d)
2
N2 1
2
At this point we are ready to return to Eq. 34g and make use of Eq. 32d and Eq. 33 to obtain
( M
)
( M
) 2 1 Y Y
(45)
CO
4
CO
2
2
2
This result can be used with Eq. 44b to provide the molar flow rate of carbon dioxide ( CO ) entering the splitter
2
( M
)
2 1 Y Y
(46)
CO
4
2
This result can be used with Eq. 34g to determine the molar flow rate of nitrogen ( N ) entering the splitter as
2
2 1
Y
1
( M
)
1 (1 C CY)
(47)
N2 4
2
CY
Y
318