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Engineering LibreTexts

5.4: The if Statement

  • Page ID
    136639
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    The simplest branch in MATLAB is the if statement. An if statement tells MATLAB: run this block of code only if the condition is true.

     

    if condition
        action
    end

     

    The word if begins the branch. The condition is the question MATLAB evaluates. The action is the code that runs only when the condition is true. The word end marks the end of the branch.

     

    Example: Square Root of a Number

    Suppose we want to calculate the square root of a number. If the user enters a negative number, we will convert it to a positive number first.

    number = input('Please enter a number: ');
    
    if number < 0
        number = -1 * number;
    end
    
    numRoot = sqrt(number);
    
    fprintf('The square root of %.1f is %.2f.\n', number, numRoot);

    If the user enters 9, the condition number < 0 is false, so MATLAB skips the action inside the if statement. If the user enters -9, the condition is true, so MATLAB multiplies the number by -1 and then continues with the rest of the program.

     

    Example \(\PageIndex{1}\)

    Square Root of a Number.

    number = input('Please enter a number: ');
    
    if number < 0
        number = -1 * number;
    end
    
    numRoot = sqrt(number);
    
    fprintf('The square root of %.1f is %.2f.\n', number, numRoot);

     

     

    Note

    MATLAB also has a built-in function called abs that returns the absolute value of a number. In this example, number = abs(number) would also convert a negative input to a positive value.

     

     

    In many programs, the if statement is used to validate user input. In the following example, we want the user to enter a positive integer diameter less than or equal to 10. Only then will MATLAB calculate the area of the circle.

    Example \(\PageIndex{2}\)

    Checking for a valid input.

    % circleArea.m
    
    % This script calculates the area of a circle if the diameter is valid.
    
    diam = input('Please enter an integer larger than 0 and less than or equal to 10: ');
    
    if diam > 0 && diam <= 10 && diam == round(diam)
        area = pi * (diam/2)^2;
        fprintf('The area of a circle with diameter %.1f is %.2f.\n', diam, area);
    end
    Solution

    If the user enters 5, for example, the displayed message will be: The area of a circle with diameter 5.0 is 19.63.

    If the user enters a negative number, nothing happens.

     

    The above example works, but it has one weakness: if the input is invalid, nothing happens. The user may not know what went wrong. That is why the if-else statement is often more helpful.

     


    5.4: The if Statement is shared under a CC BY-NC-SA license and was authored, remixed, and/or curated by LibreTexts.

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