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12.4: Drag Force

  • Page ID
    84747
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    A simple model for the drag force on a baseball is

    \[\textbf{F}_\mathrm{d} = - \frac{1}{2} \, \rho v C_\mathrm{d} A \hat{\textbf{V}}\notag \]

    where \(\textbf{F}_\mathrm{d}\) is a vector that represents the force on the baseball due to drag, \(\rho\) is the density of air, \(C_\mathrm{d}\) is the drag coefficient, and \(A\) is the cross-sectional area.

    \(\textbf{V}\) is the baseball’s velocity vector, \(v\) is the magnitude of \(\textbf{V}\), and \(\hat{\textbf{V}}\) is a unit vector in the same direction as \(\textbf{V}\). The minus sign at the beginning means that the result is in the opposite direction to \(\textbf{V}\).

    The function in Listing 12.2 computes the drag force on a baseball:

    Listing 12.2: A function that calculates the drag force on a baseball

     function res = drag_force(V)
        C_d = 0.3;      % dimensionless
        rho = 1.3;      % kg / m^3
        A = 0.0042;     % m^2
        v = norm(V);    % m/s
    
        res = -1/2 * C_d * rho * A * v * V;
    end

    The drag coefficient for a baseball is about 0.3. The density of air at sea level is about 1.3 kg/m3. The cross-sectional area of a baseball is 0.0042 m2.

    Now we have to update acceleration to take drag into account:

    function res = acceleration(t, P, V)
        g = 9.8;                       % acceleration due to gravity in m/s^2
        a_gravity = [0; -g];
    
        m = 0.145;                     % mass in kilograms
        a_drag = drag_force(V) / m;
        res = a_gravity + a_drag;
    end

    As in Listing 12.1, acceleration represents acceleration due to gravity with a vector that has magnitude g and direction along the negative y-axis. But now it also computes drag force and divides by the mass of the baseball to get acceleration due to drag. Finally, it adds a_gravity and a_drag to get the total acceleration of the baseball.

    Figure 12.3 shows the following quantities graphically: (1) acceleration due to drag, \(\textbf{D}\), which is in the opposite direction to (2) velocity, \(\textbf{V}\); (3) acceleration due to gravity, \(\textbf{G}\), which is straight down; and (4) total acceleration, \(\textbf{A}\), which is the sum of \(\textbf{D}\) and \(\textbf{G}\).

    12.3.jpg
    Figure 12.3: Diagram of velocity, \(\textbf{V}\); acceleration due to drag force, \(\textbf{D}\); acceleration due to gravity, \(\textbf{G}\); and total acceleration, \(\textbf{A}\)

    Figure 12.4 shows the results from ode45. The ball lands after about 5 s, having traveled less than 150 m, substantially less than what we got without air resistance, about 250 m.

    12.4.jpg
    Figure 12.4: Simulated flight of a baseball including drag force

    This result suggests that ignoring air resistance is not a good choice for modeling a baseball.


    This page titled 12.4: Drag Force is shared under a CC BY-NC 4.0 license and was authored, remixed, and/or curated by Allen B. Downey (Green Tea Press) via source content that was edited to the style and standards of the LibreTexts platform.